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5x^2+96=48
We move all terms to the left:
5x^2+96-(48)=0
We add all the numbers together, and all the variables
5x^2+48=0
a = 5; b = 0; c = +48;
Δ = b2-4ac
Δ = 02-4·5·48
Δ = -960
Delta is less than zero, so there is no solution for the equation
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